rnelsonchem Member

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  • This is based on simple thermodynamics. For example: 8 oz of water ~ 230 grams Body temp ~ 37 deg C Specific Heat (water) = 4.179 J/(deg C * grams) = 1 calorie/(deg C * grams) = 0.001 Calorie/(deg C* grams) Assume your glass of water is at 0 deg C (ice cold). You can calculate the heat necessary to change the temperature…
    in drinking cold water burns calories Comment by rnelsonchem July 2015
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