Stoichiometry HELP!!!!
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Pandasarecool
Posts: 508 Member
Any one know anything about Stoichiometry? I am SO lost and I have a test coming up, any help at all is appreciated!!!!
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Replies
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Yeah, post your problem.
Not had inorganic in a while, but I was pretty good at it.0 -
Well here's one: (numbers after letters are subscript)
One type of rocket engine uses the following reaction to develop thrust:
7H202 + N2H4 (arrow) 2HNO3 + 8H2O
If a rocket engine has 11.2 kg of N2H4 in it, what is the minimum mass of H2O2 necessary to allow the N2H4 to react completely?
After much struggle, I got the answer to this, BUT I wasn't quite sure how I got it. I need to understand it fully for the test though.
Thanks!0 -
There are 7 moles of hydrogen peroxide used up per mole of hydrazine in the reaction.
11.2 kg gives you how many moles if hydrazine are going to be used. (You'll actually find this # in grams).
So just multiply how many moles 11.2 kg of hydrazine is by 7 (since 7 moles of hydrogen peroxide are used per mole of hydrazine) nd then multiply that number by th molecular weight of the hydrogen peroxide to get your answer.
You're actually lucky you were given a balanced equation to start...0 -
OMG This was my favorite!!! Too bad I don't remember what to do.... O_o exactly..
But, this really helps me when I did it.
Also, make sure you balance the equation before you start.
http://www.chemtutor.com/images/roadmap.gif
http://www.chemteam.info/Stoichiometry/Stoich-Flowchart.GIF
Lucky for you it's an easy question and KG is already mass && the equation is already balanced!!
So 4.94 x 10^18 for N2H4 and 2.22 x 10^19 for H2O
.___. I hope that wasn't too confusing.. If I was on my A game I'd be able to break it down for you. Hopefully someone who is come's along though if you don't.Hopefully that helped some, at least.
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There are 7 moles of hydrogen peroxide used up per mole of hydrazine in the reaction.
11.2 kg gives you how many moles if hydrazine are going to be used. (You'll actually find this # in grams).
So just multiply how many moles 11.2 kg of hydrazine is by 7 (since 7 moles of hydrogen peroxide are used per mole of hydrazine) nd then multiply that number by th molecular weight of the hydrogen peroxide to get your answer.
You're actually lucky you were given a balanced equation to start...
Thanks, and I know, this is one of the few balanced equations I am given.:grumble: I REALLY don't like math:sick:0 -
There are 7 moles of hydrogen peroxide used up per mole of hydrazine in the reaction.
11.2 kg gives you how many moles if hydrazine are going to be used. (You'll actually find this # in grams).
So just multiply how many moles 11.2 kg of hydrazine is by 7 (since 7 moles of hydrogen peroxide are used per mole of hydrazine) nd then multiply that number by th molecular weight of the hydrogen peroxide to get your answer.
You're actually lucky you were given a balanced equation to start...
Thanks, and I know, this is one of the few balanced equations I am given.:grumble: I REALLY don't like math:sick:
Most of the work in freshman chemistry is just algebra with fancy names or units for x/y*y/z=x/z0 -
Aw...a flash back! But must say my preference is for quantum mechanics.
ETA...I just had a total geek moment didn't I? Lol.0 -
Aw...a flash back! But must say my preference is for quantum mechanics.
ETA...I just had a total geek moment didn't I? Lol.
I liked organic myself. In 2nd semester I had a 96 average when a 72 avg. got an A. I was not well liked by students outside my group in that class...0 -
Aw...a flash back! But must say my preference is for quantum mechanics.
ETA...I just had a total geek moment didn't I? Lol.
I liked organic myself. In 2nd semester I had a 96 average when a 72 avg. got an A. I was not well liked by students outside my group in that class...0
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