Database

paulelliot02
paulelliot02 Posts: 14 Member
edited 3:46AM in Food and Nutrition
Can anyone tell me how many calories in 5.5 oz. (cooked) of broiled farm-raised salmon? This database has wildly disparate information. Thanks.

Replies

  • janejellyroll
    janejellyroll Posts: 25,763 Member
    Have you tried looking at USDA information?
  • r3488
    r3488 Posts: 77 Member
    @HellYeahItsKriss made an awesome post on how to use the database (with screenshots): http://community.myfitnesspal.com/en/discussion/10621050/how-to-use-the-usda-food-database-mfp-food-database-for-accurate-logging/p1
  • paulelliot02
    paulelliot02 Posts: 14 Member
    Thank you so much, but I still cannot figure this out. I'll be eating 5.5 oz of broiled farm-raised Atlantic salmon. I entered 5.5 in the gram section but the result is around 350 calories. I don't think that's correct. Would be great if the database provided filters.
  • r3488
    r3488 Posts: 77 Member
    If oz is not available in the serving unit drop down list, you can google "convert 5.5 oz to grams" and it should give you the amount in grams (1 oz is approximately 28.35 grams).
  • DaintyWhisper
    DaintyWhisper Posts: 221 Member
    edited February 2018
    This is the nutrition information I would use: https://tinyurl.com/y7fxyp43
    According to that, there is 206 calories in 100 grams of the salmon. 5.5oz is about 156 grams. Search the food database for "Atlantic salmon dry heat 100g" and find the entry that says 206 calories with 100 grams as the serving. For your serving size, put in 1.56 of a serving. It should be about 321 calories. It might take a little bit of getting used to, but I find measuring in grams to be a lot easier! Good luck~
  • paulelliot02
    paulelliot02 Posts: 14 Member
    Now I'm looking for calories in boiled, skinless chicken breast 4 oz. yield. Again, this database is all over the place! Can anyone nail this for me? I have it all the time and would love some consistency. Thanks very much.
  • lemurcat12
    lemurcat12 Posts: 30,886 Member
    If you get familiar with the USDA site, you will learn to recognize good USDA entries in the database. They usually have lots of measurement options (oz, g), also. It's here: https://ndb.nal.usda.gov/ndb/search/list

    The key with chicken is to use an entry based on whether it was raw or cooked when you weighed it (if the weight is on the package and you want to use that, it's a raw weight).

    Raw chicken breast, skinless is: 05062, Chicken, broiler or fryers, breast, skinless, boneless, meat only, raw and 136 cal for 4 oz.

    If the chicken breast is really BOILED (sounds unappealing, do you mean BROILED?), then I'd use the entry for cooked, stewed: 05065, Chicken, broilers or fryers, breast, meat only, cooked, stewed

    That has 172 cal for 4 oz (for some reason I only see grams, so did the conversion, personally I prefer using grams anyway).



  • paulelliot02
    paulelliot02 Posts: 14 Member
    Thanks for the info. BTW, if you brine the chicken and rinse before gently simmering you'll get an amazingly tasty treat. I throw in a couple of Star Anise among other things for the brine. Check it out. How come you prefer grams?
  • paulelliot02
    paulelliot02 Posts: 14 Member
    I see everything BUT calories on that site for 05065.
  • lemurcat12
    lemurcat12 Posts: 30,886 Member
    edited April 2018
    Energy=calories.

    Grams are more precise (unless you do 4.12 oz or the like, and then it makes oz even harder to work with). I like grams being in units of 100, and with experience I can eyeball what 100 g of potato or broccoli or whatever is. Even though I'm American enough to like lbs (I know what 120 lb means), I'm annoyed by the 16 oz to a lb thing.

    I do think it's best to use grams also because most food labels use grams as their weight measure (other than butcher counters, and I get my meat from a farm so have to weigh it myself). When you weigh and get 116 g, it's so easy to be able to pick the 100 g unit and put in 1.16.

    Ultimately, though, it's personal preference.
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