drinking cold water burns calories

weinman2015

I read that when you drink icy cold water that your body has to expend energy to stay at 98.6 degrees. allegedly you burn eight calories when you drink a cold glass of water.

If you have any more info on this or heard that it's a myth then by all means leave a comment

Hea1thyGam3r

Your body does expend energy to warm the water up.. whether or not it is 8 calories worth I doubt anyone knows for sure. It also does things like interfere with your digestion though.. Unless you are nitpicking the calories burned in drinking a cold glass of water vs a room temperature glass just don't matter.

SubZeroDude

I thought that it just helps you use more cals from carbs as energy, like, helps your energy use to burn calories be more efficient

weinman2015

Interesting.interfere with your digestion? That's sound not good

BasicGreatGuy

Sounds like you should stick to accredited journals.

weinman2015

Could be.I need to research this more

Hea1thyGam3r

Yeah, it's true that a well hydrated body does everything better, including digestion.. but when you are drinking ice water while you eat you are actually temporarily changing the PH of your stomach acid and bile. There was a research paper on it, and I may be explaining it inacurately, but if I can find it I will send it to you.

weinman2015

BasicGreatGuy wrote: »

Sounds like you should stick to accredited journals.

Lol.right!

SubZeroDude

Sounds like broscience, man. plus, even if it's true, I wouldn't bother counting 8 calories burned.

cwolfman13

majoring in the minors....you might burn a calorie or two more by expending energy to get your core temperature back up...maybe...but hardly worth putting any energy into figuring out exactly how much or making sure all of my water is ice cold.

also, you know you burn calories 24/7 right...even when you're doing absolutely nothing.

weinman2015

True, I just figured that if someone drinks ten glasses a day that they could chill them first and burn eighty cals.little things like that and parking at the very end of the barking lot so you have to walk further.it all adds up ya know

weinman2015

cwolfman13 wrote: »

majoring in the minors....you might burn a calorie or two more by expending energy to get your core temperature back up...maybe...but hardly worth putting any energy into figuring out exactly how much or making sure all of my water is ice cold.

also, you know you burn calories 24/7 right...even when you're doing absolutely nothing.

Yeah I just heard that in a documentaries.its like two to three a min just to keep your system going.

yellowantphil

It takes a few calories to heat up cold water in your stomach. It also takes a few calories to pick up the glass of water.

For a glass of water from the fridge, it takes about 12 calories to heat up: energy required to heat 12 fl oz of water from 40 °F to 98.6 °F in kcal. You might be able to eat a chocolate chip with your extra calories after drinking a couple glasses of cold water.

weinman2015

Lol.

yellowantphil wrote: »

It takes a few calories to heat up cold water in your stomach. It also takes a few calories to pick up the glass of water.

For a glass of water from the fridge, it takes about 12 calories to heat up: energy required to heat 12 fl oz of water from 40 °F to 98.6 °F in kcal. You might be able to eat a chocolate chip with your extra calories after drinking a couple glasses of cold water.

Is that just a chocolate chip or a whole cookie?

rnelsonchem

This is based on simple thermodynamics. For example:

8 oz of water ~ 230 grams
Body temp ~ 37 deg C
Specific Heat (water) = 4.179 J/(deg C * grams) = 1 calorie/(deg C * grams) = 0.001 Calorie/(deg C* grams)

Assume your glass of water is at 0 deg C (ice cold). You can calculate the heat necessary to change the temperature using the following equation:

Heat = Specific Heat * Mass * Temp Change
= 0.001 Calorie/(deg C*grams) * 230 grams * (37 deg C - 0 deg C)
= 8.51 Calorie

Also, the definition of a dietary calorie (Calorie) is

approximately the amount of energy needed to raise the temperature of one kilogram of water by one degree Celsius

So a 37 deg C temp change would be 37 Cal for 1000 grams of water. Since we only have 230 grams of water in our glass 37 Cal * (230/1000) = 8.51 Cal -- same as above.

...Not that you'd actually want to drink ice-cold water all the time...

weinman2015

rnelsonchem wrote: »

This is based on simple thermodynamics. For example:

8 oz of water ~ 230 grams
Body temp ~ 37 deg C
Specific Heat (water) = 4.179 J/(deg C * grams) = 1 calorie/(deg C * grams) = 0.001 Calorie/(deg C* grams)

Assume your glass of water is at 0 deg C (ice cold). You can calculate the heat necessary to change the temperature using the following equation:

Heat = Specific Heat * Mass * Temp Change
= 0.001 Calorie/(deg C*grams) * 230 grams * (37 deg C - 0 deg C)
= 8.51 Calorie

Also, the definition of a dietary calorie (Calorie) is

approximately the amount of energy needed to raise the temperature of one kilogram of water by one degree Celsius

So a 37 deg C temp change would be 37 Cal for 1000 grams of water. Since we only have 230 grams of water in our glass 37 Cal * (230/1000) = 8.51 Cal -- same as above.

...Not that you'd actually want to drink ice-cold water all the time...

Damn,that's was very informative.thanks bro

yellowantphil

weinman2015 wrote: »

Lol.

yellowantphil wrote: »

It takes a few calories to heat up cold water in your stomach. It also takes a few calories to pick up the glass of water.

For a glass of water from the fridge, it takes about 12 calories to heat up: energy required to heat 12 fl oz of water from 40 °F to 98.6 °F in kcal. You might be able to eat a chocolate chip with your extra calories after drinking a couple glasses of cold water.

Is that just a chocolate chip or a whole cookie?

Oh wait, you can have two chocolate chips per 12 fl oz of 40 °F water. One chocolate chip is 5 calories. Just the chips—no cookies.

Hea1thyGam3r

rnelsonchem wrote: »

This is based on simple thermodynamics. For example:

8 oz of water ~ 230 grams
Body temp ~ 37 deg C
Specific Heat (water) = 4.179 J/(deg C * grams) = 1 calorie/(deg C * grams) = 0.001 Calorie/(deg C* grams)

Assume your glass of water is at 0 deg C (ice cold). You can calculate the heat necessary to change the temperature using the following equation:

Heat = Specific Heat * Mass * Temp Change
= 0.001 Calorie/(deg C*grams) * 230 grams * (37 deg C - 0 deg C)
= 8.51 Calorie

Also, the definition of a dietary calorie (Calorie) is

approximately the amount of energy needed to raise the temperature of one kilogram of water by one degree Celsius

So a 37 deg C temp change would be 37 Cal for 1000 grams of water. Since we only have 230 grams of water in our glass 37 Cal * (230/1000) = 8.51 Cal -- same as above.

...Not that you'd actually want to drink ice-cold water all the time...

Which is all well and good but you are missing a +/- variable that makes this pretty much useless. Not everyone runs at the same temperature and depending on the time of day and a thousand other factors our bodies are going to vary in temperature, internally. I realize this is nitpicking and that the end result is going to be 6-12 calories burned but in the end it just doesn't matter. 6-12 calories do not make a difference, even over time because our bodies don't operate on the micro scale.

yellowantphil

The real question is, how many calories have we burned typing in this thread? Can I eat another chocolate chip yet to get my calories back?

Hea1thyGam3r

The answer to that, Yellow, is always... Yes!

Cindy4FunFit

And if you add & crunch ice...you burn like a fraction of a fraction of a fraction's fraction more. But I'm not doing any math right now.

ninerbuff

Just adding to the confusion: the calculations could be off because that's raising the temperature of water in a container. One doesn't consume that much water in a single gulp, so it's taken in small amounts at a time. Since there is more surface area now affected by heat (swallowing a "stream" of water) it takes less energy to heat it up.
Sip a slurpee. Once it hits your mouth, it's almost automatically liquified in a few seconds.

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