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totally random --- anyone good at Organic Chemsitry?
I need help on my homework its kicking my *kitten*
Help?
Also How can I get an image of the question into here? I don't have flikr or photobucket...
OH i'll add it as a picture of me, it'd probably be too small tho... well help with that too please!
Help?
Also How can I get an image of the question into here? I don't have flikr or photobucket...
OH i'll add it as a picture of me, it'd probably be too small tho... well help with that too please!
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Replies
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I did take an Organic Chem. class at one point, but I think I barely passed LOL!
If you ever have math/physics questions, give me a shout0 -
Oddly enough, I'm a chemist... While organic wasn't always my fav (I'm more analytical/inorganic), I might be able to help.0
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im great at organic chem whats the question0
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Had to re-take orgo 2, so it kinda got drilled into my head, but that was a few years ago and has probably been replaced by other slightly more useful knowledge. But maybe I remember enough to help.0
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The subject we are on is Alkenes and Alkeynes Addition reactions, that should give you a reference.
We are given hepta-1,6-diene and it reacts with catalytic H+ and I am supposed to guess the two constitutional isomer products
The hints we are given:
Composition of the products is C7H12
Both isomers react with one equiv. of Br20 -
When's the assignment due? All my organic books are at work...0
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I think the answers are hept-6-en-2-ylium but the composition of that is C7H13!!!!
UGH!!
We are also asked to predict the products if the same reactant reacts with KMnO4, OH-, and heat0 -
Tomorrow morning 11am. I am a true procrastinator =]0
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Well, I'll check back in the morning at 7:30 ish. If you don't have the answer by then, I'll work on it.0
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The subject we are on is Alkenes and Alkeynes Addition reactions, that should give you a reference.
We are given hepta-1,6-diene and it reacts with catalytic H+ and I am supposed to guess the two constitutional isomer products
The hints we are given:
Composition of the products is C7H12
Both isomers react with one equiv. of Br2
Can you give the actual question as it is written?
I aced organic chem, but I need to know how the question is being asked.... (sort of a quirk, but its the type of thinker I am...)0 -
Draw bond-line structures of the products corresponding to each boldfaced letter in the following
reaction sequence. The composition of A and B is C7H12. Both react with only one equiv of Br2.
...................................................... catalytic H+
((Drawing of hept-1,6-diene))
> A + B (constitutional isomers)
|
| KMnO4, OH-, heat
|
C
I need to find products A+B+C0 -
In the rxn for C, the fact that there is heat added makes me think its an elimination reaction, We always learned that heat was elimination. And its a small base, so probably E2 right?0
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My brain hurts... Turns out Orgo has been blocked from my memory. Probably too traumatic.0
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My brain hurts... Turns out Orgo has been blocked from my memory. Probably too traumatic.
Yeah I don't blame you. Unfortunately I'll probably need this crap for my career.
I'm going into biomedical engineering. Yay for the hardest major at my school!!!!0 -
In the rxn for C, the fact that there is heat added makes me think its an elimination reaction, We always learned that heat was elimination. And its a small base, so probably E2 right?
I am having difficulty recreating the bond diagram (im too much a visual learner that I need the images)
as soon as I get all that straight I will get it....
lol0 -
http://www.google.com/imgres?imgurl=http://www.chemeddl.org/alfresco/d/d/workspace/SpacesStore/5fcf2224-15e9-4712-8b14-af63cc77d4c2/hept-1-ene.png?guest=true&imgrefurl=http://www.chemeddl.org/alfresco/service/org/chemeddl/ttoc/ttoc_results/?id=20957&mode=primary&type=molecule&num_results=§ion=§itle=&guest=true&usg=__9RRxzKHNDv9jtJ9tPMpZG7wdWCI=&h=108&w=165&sz=2&hl=en&start=0&sig2=JZr-EQc8BOBIwicBFuz6FA&zoom=1&tbnid=yph2QF-aLTPPcM:&tbnh=86&tbnw=132&ei=9jmVTd6LO9G90QH2qICGDA&prev=/images?q=hept-1,6-diene&um=1&hl=en&sa=N&biw=1028&bih=892&tbs=isch:1&um=1&itbs=1&iact=hc&vpx=193&vpy=423&dur=2025&hovh=86&hovw=132&tx=101&ty=53&oei=9jmVTd6LO9G90QH2qICGDA&page=1&ndsp=22&ved=1t:429,r:8,s:0
Thats the picture, except there is another double bond on the other end of the carbon chain also0 -
Im sorry I couldn't get to you,
I kept getting something that didn't quite work out.
Hopefully you were able to figure out the assignment....0
This discussion has been closed.
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