Math
SymphonynSonata
Posts: 533 Member
in Chit-Chat
Container A is 250ml and contains a mixture of milk and water; it is 30% milk to 70% water. Container B is 250ml and contains 100% milk. Container C is 250ml. How much milk from container B do I have to mix to have 70% milk and 30% water?
All jars are full except for container C. Container C will be where it is mixed.
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I've found a calculator that says I would need to add 107.11ml of the 30/70 and 132.89ml of the pure milk to arrive at 70.01/29.99. I don't know how to arrive to this.
All jars are full except for container C. Container C will be where it is mixed.
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I've found a calculator that says I would need to add 107.11ml of the 30/70 and 132.89ml of the pure milk to arrive at 70.01/29.99. I don't know how to arrive to this.
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Replies
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175ml0
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175 ml =D
Am I right??!?0 -
Given that cow's milk is already at 80% water...the jar isn't big enough.0
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I've found a calculator that says I would need to add 107.11ml of the 30/70 and 132.89ml of the pure milk to arrive at 70.01/29.99. I don't know how to arrive to this.0
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Math is hard. I'm just going to sit here and look pretty.
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I'm just here because I'm not wearing my glasses and thought the title was "meth." I. Am. Disappoint.0
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Edited top post to include my later posts
and to bump this for the higher chance of someone answering0 -
You need 142.86ml of the 30% milk solution, and 107.14 ml of the 100% milk solution for 250ml of 70% milk.
Sounds like an awful lot of work, though...0 -
You need 142.86ml of the 30% milk solution, and 107.14 ml of the 100% milk solution for 250ml of 70% milk.
Sounds like an awful lot of work, though...
Your answer is really close to what the calculator said! (107.11ml of the 30/70 and 132.89ml of the pure milk to arrive at 70.01/29.99), just kinda backwards? Maybe I'm backwards? How'd you get to this?0 -
3/7A + 4/7B
107ml A + 143ml B0 -
3/7A + 4/7B
107ml A + 143ml B
HOWWWWWWWWWWWW0 -
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depends, if you have to mix the 2 together you would need 57.1% of B and 42.9% of A, this would give you a full 250ml jar C that would end up being 70% just milk... there is a little rounding as this just gives you 69.97% Milk0
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I'm just here because I'm not wearing my glasses and thought the title was "meth." I. Am. Disappoint.
I thought it was about meth too!!0 -
Just break up.0
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3/7A + 4/7B
107ml A + 143ml B
HOWWWWWWWWWWWW
All the containers are 250ml so you can just use the percentages to work out how much you need which is easier!
If container A has 70% water and you want 30% water in container C, then you need to divide 30 by 70 to find out what ratio you need. So 3/7 x 70% = 30%
As container B is entirely milk, you just need to fill container C to 100% and what's in it must be 70% milk because you've already worked out the 30% water.
So if you've got 3/7 of A, to make 100% of C, you'll need 4/7 of B.0 -
Container A is 250ml and contains a mixture of milk and water; it is 30% milk to 70% water. Container B is 250ml and contains 100% milk. Container C is 250ml. How much milk from container B do I have to mix to have 70% milk and 30% water?
All jars are full except for container C. Container C will be where it is mixed.
xA + xB = 250
xA*0.7 = 250*0.3
Solve.
ETA:
Gandalfina above me!0 -
I hope I can explain it without the chart that I use...
The common factor in the two solutions is the milk, so consider one to be 100% milk and one to be 30% milk. When combined, you want to create a 70% solution, therefore you subtract 70 from each of the percentages to determine how many parts of each solution you need:
100-70=30 parts of the 100% solution
70-30=40 parts of the 30% solution.
When you add the parts together, that will equal the total amount of solution you want to create:
30+40=70 parts -- 70 parts=250ml (since that is the container size you have)
From there, it is a conversion equation:
70 parts/250ml = 40 parts/x ml
Cross multiply and divide. Once you know how many ml of the 30% solution you need (the 40 parts), you can subtract that number from 250 to determine how much of the other solution (100%) you need.
And now I need more caffeine. Too much math! :laugh:0 -
But why are you mixing water with milk?0
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No mas pantalones!0
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Math is Hard and I just went....
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No mas pantalones!0
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Math is hard. I'm just going to sit here and look pretty.
Brain hurt......can't figure out...... OOO look David Boreanaz yum!!0 -
No mas pantalones!
No me gustan math. No es bueno. Cervesa por favor? Grassy *kitten*.0 -
I hope I can explain it without the chart that I use...
The common factor in the two solutions is the milk, so consider one to be 100% milk and one to be 30% milk. When combined, you want to create a 70% solution, therefore you subtract 70 from each of the percentages to determine how many parts of each solution you need:
100-70=30 parts of the 100% solution
70-30=40 parts of the 30% solution.
When you add the parts together, that will equal the total amount of solution you want to create:
30+40=70 parts -- 70 parts=250ml (since that is the container size you have)
From there, it is a conversion equation:
70 parts/250ml = 40 parts/x ml
Cross multiply and divide. Once you know how many ml of the 30% solution you need (the 40 parts), you can subtract that number from 250 to determine how much of the other solution (100%) you need.
And now I need more caffeine. Too much math! :laugh:
Thank you so much (and everyone else too!) I tried to follow this on paper and got kinda confused in the last part. I cross multiplied, but IDK if I did that right. I ended up with:
70 40
---- x
= 70x/10000 which I worked down to 7/1000, then divided and got .007
250 x
and then I got completely lost0 -
This problem is worded poorly, and whomever initially wrote it should be made an indentured servant to a "Mathnasium" . :sick:
:Edited to resize image for MFP borders:0 -
I knew my math degree would come in handy one day but now I just cant be bothered. TL;DR0
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I knew my math degree would come in handy one day but now I just cant be bothered. TL;DR
Love your username! Life, the Universe and Everything! :drinker:0
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