How Many Calories A Day ( Advice Needed )

I know that 1200 calories is minimum for a person , but is that assuming a person maintains on 2000? Because I maintain on 1800 so I was wondering if it is safe to take it down to 1000 ?


  • editorgrrl
    editorgrrl Posts: 7,060 Member
    To lose 12 lbs. set your goal to .5 lb. per week (a 250-calorie deficit), and be patient. Eating a 1,000-calorie deficit will not get you to your goal 4x faster. The less you have to lose, the more slowly it comes off. That's just the way the human body works.

    Please, read the Sexypants post:
  • 126siany
    126siany Posts: 1,386 Member
    If you only have 12 pounds to go, you should set your goals to lose .5 lbs a week. That would actually be a 250 calorie deficit per day.

    When you enter your information into MFP with that goal, what does it give you for a daily calorie goal?
  • vismal
    vismal Posts: 2,463 Member
    Is it safe? Depends what you mean by safe. It won't kill you to eat 1000 calories. Your body won't shut down fat loss, or anything crazy like that. What will happen is you may find yourself feeling awful, wanting to binge eat, having low to very low energy, poor sleep, etc. Part of why very low calories don't work is that they don't create as big of a deficit as you think they would. If you maintain on 1800 and cut to 1000 you might find that you are far less active for the day due to low energy levels. This is in turn means your TDEE is lower. I'd much rather prefer to eat a little more, and burn more calories by being active, then restrict my calories to such a low level. Remember that eating 1000 calories and burning 1500 is the same net difference as eating 1500 calories and burning 2000. Accept the person eating 1500 is less likely to miss out on vital nutrients because they have more calories to work with at the end of the day.
  • perrinjoshua
    perrinjoshua Posts: 286 Member
    I think the two experienced dieters that have lost a lot of weight have the right idea. Listen to their advice, I would.